Calculation of the chimney

Calculation of the chimney

Example

A chimney with a channel cross-section was designed in the wooden house 3 x 14 x 14 cm and height 7 m. How much materials do you need to build?

Solution

Chimney cross-sectional area = 0,38 m x 0,90 m = 0,342 m2

Chimney volume = cross-sectional area x chimney height = 0,342 m2 x 7,0 m = 2,394 m3 = 2,4 m3

The amount of materials needed for construction:
ceramic brick full of class 100(150) = 2,4 m3 x 388 szt./m3 = 931 pcs.
cement-lime mortar Rz 30 = 2,4 m3x 0,216 m3/m3 = 0,518 m3

(1:1:6), including:
construction cement 250 = 2,4 m3 x 50 kg/m3 = 120 kg
hydrated lime = 2,4 m3 x 28 kg/m3 = 67 kg
mortar sand = 2,4 m3 x 517 kg/m3 = 1241 kg
water = 2,4 m3 x 123 dm/m3 = 295 dm3

For execution 1,00 m3 of a single-circuit chimney with a channel cross-section 14 x 14 cm needed:
building brick full of class 100(150) -388pcs.
cement-lime mortar Rz 30 (1:1:6), -0,216 m3

including:
construction cement 250 – 50 kg
hydrated lime – 28 kg
mortar sand – 517 kg
water -123dm3

For execution 1,00 m3 of a single-circuit chimney with a channel cross-section 27 x 27 cm needed:
building brick full of class 100(150) – 374 pcs.
cement-lime mortar Rz 30 (1:1:6), – 0,254 m3

including:
construction cement 250 – 49 kg
hydrated lime – 27 kg
mortar sand – 503 kg
water -120dm

For execution 1,00 m3 of a single-circuit chimney with a channel cross-section 14 x 27 cm needed:
building brick full of class 100(150) -388 pcs.
cement-lime mortar Rz 30 (1:1:6), – 0,246 m3

including:
construction cement 250 – 47 kg
hydrated lime – 26 kg
mortar sand – 488 kg
water -116dm3

For execution 1,00 m3 of a double-circuit chimney with a channel cross-section 2 x 14 x 27 cm needed:
building brick full of class 100(150) -314 pcs.
cement-lime mortar Rz 30 (1:1:6), – 0,207 m3

including:
construction cement 250 – 40 kg
hydrated lime – 22 kg
mortar sand – 410 kg
water – 97 dm3